Just a correction to my pp.x input file:
I actually used cartesian coordinates for the e1 and x0. So
0.3571863 0.2721583 0.1838386 for x0 and
0.1171583 0.2721583 0.1535005 for e1.
Vahid
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Dear QE Users,
In order to calculate the total potential along one of the SnSe bonds
(Se2-Sn4), I first performed a self-consistent run with the following lattice
parameters.
ibrav=8, celldm(1)=21.34350847, celldm(2)=0.3628777, celldm(3)=0.38586894
Sn 0.882841736 0.250000000 0.602195343
Sn 0.617158264 0.750000000 0.102195343
Sn 0.382841736 0.250000000 0.897804657
Sn 0.117158264 0.750000000 0.397804657
Se 0.142813748 0.250000000 0.976427467
Se 0.357186252 0.750000000 0.476427467
Se 0.642813748 0.250000000 0.523572533
Se 0.857186252 0.750000000 0.023572533
I then ran pp.x with the following input:
&inputpp
prefix = 'SnSe'
filplot = 'potential.dat'
plot_num= 1
/
&plot
iflag=1
output_format=0
nfile = 1
filepp(1) = 'potential.dat'
e1(1)=0.117158264, e1(2)=0.750000000, e1(3)= 0.397804657,
x0(1)=0.357186252, x0(2)= 0.750000000, x0(3)=0.476427467,
nx=100,
fileout= 'VSe2_Sn4.dat’
/
The bond length is 2.73A=5.16Bohr. Attached is the output of potential vs.
distance. The x-axis runs from 0 to ~0.33. According to other links in the
Forum, the x-axis is in atomic units. Two possibilities:
1. The distance is in Bohr. So is the pp.x code plotting from 0 to 0.33 Bohr
even though the bond length is 5.16Bohr as defined by the vectors x0 and e1?
2. The distance is in alat. Then 0.33*alat=7.04Bohr. This is longer than the
bond length.
So what is the unit of the x-axis?
Thank you,
Vahid
Vahid Askarpour
Department of Physics and Atmospheric Science
Dalhousie University,
Halifax, NS, Canada
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