Dear all, After reading through the related source codes, I think I have got the solution. The unit of N(Ef) in electron phonon calculations is states/Ry.
Thank you very much. Bests Yuewen 2018-01-28 19:56 GMT+09:00 Yue-Wen Fang <[email protected]>: > Dear all, > > In the example03 of PHonon, the output is: > > lambda = 0.290653 ( 0.290650) <log w>= 394.512K N(Ef)= 1.338761 > at degauss=0.005 > > lambda = 0.433066 ( 0.431806) <log w>= 354.413K N(Ef)= 1.881758 > at degauss=0.010 > > lambda = 0.423533 ( 0.420938) <log w>= 342.551K N(Ef)= 2.123243 > at degauss=0.015 > > lambda = 0.394886 ( 0.392086) <log w>= 337.523K N(Ef)= 2.249755 > at degauss=0.020 > > lambda = 0.373648 ( 0.371072) <log w>= 333.960K N(Ef)= 2.329819 > at degauss=0.025 > > lambda = 0.364263 ( 0.361951) <log w>= 330.940K N(Ef)= 2.396041 > at degauss=0.030 > > lambda = 0.363628 ( 0.361498) <log w>= 328.520K N(Ef)= 2.455234 > at degauss=0.035 > > lambda = 0.367961 ( 0.365924) <log w>= 326.679K N(Ef)= 2.507879 > at degauss=0.040 > > lambda = 0.374619 ( 0.372618) <log w>= 325.312K N(Ef)= 2.552970 > at degauss=0.045 > > lambda = 0.381512 ( 0.379521) <log w>= 324.330K N(Ef)= 2.589584 > at degauss=0.050 > > lambda omega_log T_c > > 0.29065 394.512 0.138 > > 0.43307 354.413 2.273 > > 0.42353 342.551 1.962 > > 0.39489 337.523 1.316 > > 0.37365 333.960 0.928 > > 0.36426 330.940 0.778 > > 0.36363 328.520 0.763 > > 0.36796 326.679 0.821 > > 0.37462 325.312 0.919 > > 0.38151 324.330 1.028 > > > Could anyone tell me the unit of N(Ef)? Is this value same as the one in a > density of states calculation? > > Thank you very much. > > Bests > Yuewen > -- > ------------------------------------------------------------ > ------------------------------------------------ > Yue-Wen FANG, PhD > Kyoto University, Japan > > > > -- ------------------------------------------------------------------------------------------------------------ Yue-Wen FANG, PhD Kyoto University, Japan
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