On 2020-12-11 16:38, Ming Lei wrote:
Dear Lorenzo and Marcelo,

Thank you for your reply. The Lowdin Charges I post was calculated by setting

 noncolin = .true.
 lspinorb = .true.
 angle1(1)=0.0
 angle2(1)=0.0

Yes, I had not thought about full-relativistic calculations. That said, if you do not specify any starting_magnetization, the polarization will be zero, I can tell you this without the need to do any projection. On the other hand, if you set a starting_magnetization, the pw.x code will write-out the polarization itself:


 ==============================================================================
     atom number    5 relative position :    0.0000   0.0000 0.0000
     charge :     5.377640
     magnetization :          0.000000    0.000000   -0.000000
     magnetization/charge:    0.000000    0.000000   -0.000000
     polar coord.: r, theta, phi [deg] :     0.000000  180.000000 360.000000
 ==============================================================================

I don think projwfc gives you the polarization in output in this case, but what's above may be enough for your need.


cheers




This is the case of nspin = 4 (nspin = 4 : spin-polarized calculation, noncollinear (magnetization in generic direction) DO NOT specify nspin <https://www.quantum-espresso.org/Doc/INPUT_PW.html#nspin>in this case; specify noncolin <https://www.quantum-espresso.org/Doc/INPUT_PW.html#noncolin>=.TRUE. instead). When noncolin = .true., the Lowdin charges don't have the information about atom magnetic moment.

I tried nspin = 2 before, and I had spin-up and spin-down Lowdin charges when nspin =2, but this is not a spin-polarized calculation.

So besides projwfc, is there any other way to obtain information about the atomic magnetic moment? For example, in the pp.x, plot_num = 13 is the noncollinear magnetization. But after running pp.x, I don't know how to get the atomic magnetic moment.

Ming Lei
University of California, Riverside


On Fri, Dec 11, 2020 at 3:33 AM Marcelo Albuquerque <[email protected] <mailto:[email protected]>> wrote:

    Dear Ming,

    I completely agree with Mr. Paullato, but, more precisely, in the
    case of non-collinear calculations, you have to specify nspin = 4,
    actually.
    There are other options you have to deal with in other to perform
    such a task. Please check the documentation below, as well as the
    corresponding projwfc.x one:

    https://www.quantum-espresso.org/Doc/INPUT_PW.html#idm368

    HIH.

    Best of luck.
    /
    /
    /
    /   Marcelo Albuquerque/
    //
    /     Ph.D. Candidate/
    //
    /   Physics Institute/
    //
    /Universidade Federal Fluminense (UFF)/
    /
    /     Niterói/RJ - Brazil/


    On Fri, Dec 11, 2020 at 8:00 AM Lorenzo Paulatto wrote:


        Dear Ming,

        the projwfc will compute spin-up and spin-down Lowdin charges,
        but only
        if you did include spin in your pw calculation, by setting
        nspin=2.

        kind reagrds


        On 2020-12-11 06:34, Ming Lei wrote:
        > Dear Users,
        >
        > After running projwfc.x, at the end of the output file, it shows
        >
        > Lowdin Charges:
        >
        > ? ? ?Atom # ? 1: total charge = ?13.5212, s, p, d, f =
        2.6218 ?5.9990
        > ?4.9003
        > ? ? ?Atom # ? 2: total charge = ?13.5212, s, p, d, f =
        2.6218 ?5.9990
        > ?4.9003
        > ? ? ?Atom # ? 3: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Atom # ? 4: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Atom # ? 5: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Atom # ? 6: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Atom # ? 7: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Atom # ? 8: total charge = ? 7.0913, s, p, d, f =
        1.9097 ?5.1816
        > ?0.0000
        > ? ? ?Spilling Parameter: ? 0.0059
        >
        > There is no information about the?magnetic moment of each
        atom.? So
        > how to?calculate atomic magnetic moment in the non-collinear
        > spin-orbit calculations?
        >
        > Any suggestion will?be appreciated. Thank you.
        >
        > Ming Lei
        > University of California, Riverside
        >
        > _______________________________________________
        > Quantum ESPRESSO is supported by MaX (www.max-centre.eu
        <http://www.max-centre.eu>)
        > users mailing list [email protected]
        <mailto:[email protected]>
        > https://lists.quantum-espresso.org/mailman/listinfo/users
        -------------- next part --------------
        An HTML attachment was scrubbed...
        URL:
        
<http://lists.quantum-espresso.org/pipermail/users/attachments/20201211/036b36b5/attachment-0001.html>

        ------------------------------

    _______________________________________________
    Quantum ESPRESSO is supported by MaX (www.max-centre.eu
    <http://www.max-centre.eu>)
    users mailing list [email protected]
    <mailto:[email protected]>
    https://lists.quantum-espresso.org/mailman/listinfo/users


_______________________________________________
Quantum ESPRESSO is supported by MaX (www.max-centre.eu)
users mailing list [email protected]
https://lists.quantum-espresso.org/mailman/listinfo/users
_______________________________________________
Quantum ESPRESSO is supported by MaX (www.max-centre.eu)
users mailing list [email protected]
https://lists.quantum-espresso.org/mailman/listinfo/users

Reply via email to