I fear your enterprise is destined for failure.

Performing periodic calculations on charged materials does not converge.  They 
can be made to converge by adding a jellium neutralising background, but I do 
not think that it has been proven that that is an accurate approach.  It's 
worse for slabs, where the results depend explicitly on the amount of vacuum 
between images.

I do not have a viable alternative suggestion.

Ciao
Terry

UNSW Canberra

________________________________
From: users <[email protected]> on behalf of Zhenyao 
Fang <[email protected]>
Sent: Tuesday, 17 August 2021 9:30 AM
To: [email protected] <[email protected]>
Subject: [QE-users] Total energy of charged slabs

Dear pwscf users,

I am performing some calculations on negatively charged slabs (with one 
additional electron), and I’m mainly focusing on the energy difference between 
charged system and neutral system. With ions fixed, I found that the charged 
system has a higher energy than the neutral system, instead of being lower.

The energy difference dE = E(q=-1) - E(q=0) is around 3.944 eV. The LUMO 
position of the neutral slab is 3.462 eV, and the vacuum level for the neutral 
slab is 7.654 eV. Besides, by inspecting the charge difference plots, the 
additional charge is localized inside the slab. I understand that there could 
be problems about jellium background, so I used the package “sxdefectalign2d” 
to correct the interactions due to periodic images, and the total energy of the 
charged slab remains the same as the size of vacuum increases.

I’m quite confused by the fact that the total energy would increase with one 
more electron. Since the additional charge is mainly inside the slab, it should 
lower the energy and be stabilised inside the slab. Therefore, I was wondering 
how I can reconcile these controversies. Besides, another related question is 
how we define the zero energy in QE? In other words, does LUMO larger or 
smaller than zero possibly imply the stability of the system?

I am looking forward to your replies. Thanks in advance.

Best,
Zhenyao Fang





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