```Hallo Claus,

would you like to explain, why you thought of images as input?```
```
I worked a little in the field of finding lines/edges in noisy images and a
cumsum approach crossed my way some years ago.
So maybe here, there is something to learn for me?

Best Regards,
Philipp

Am Mo., 7. Feb. 2022 um 20:18 Uhr schrieb Claus Futtrup <cfutt...@gmail.com
>:

> Hi Heinz
>
> I notice that the E-vector is longer than the largest numberin the
> EE-vector. What decides the length of the E-vector?
>
> I was thinking length(EE) = 3 gives the highest number in the E-vector,
> and that e.g. max(EE) = 8 would be the length of the E-vector (but it's
> not ...), such that E = zeros(1:maxE) could be your initialization. This
> is why I ask, what decides the length of the E-vector?
>
> How large are the numbers going to be? ... are we talking
> graphics/pictures in the mega-pixel range as input?
>
> Best regards,
> Claus
>
> On 07-02-2022 18:35, Heinz Nabielek wrote:
> >
> > Given vector EE= [3 5 8]
> >
> > I want to create a stepwise increasing vector E= [0 0 1 1 2 2 2 3 3 3 3]
> >
> > And would need a system that works for much larger numbers....
> >
> > Heinz
> >
> > _______________________________________________
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> > users@lists.scilab.org
> > http://lists.scilab.org/mailman/listinfo/users
>
>
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