Take a look at the uberjar plugin.. it handles creating the classpath... > -----Original Message----- > From: Ming Fang [mailto:[EMAIL PROTECTED] > Sent: Tuesday, October 19, 2004 4:21 PM > To: Maven Users List > Subject: Re: Maven > > > we actually copy the versioned jars to a "distribution" directory but > leave of the version number in the process. > our maven.xml looks like this > > <project > xmlns:deploy="deploy" xmlns:j="jelly:core"> > > <goal name="lib"> > <deploy:copy-deps todir="lib"/> > </goal> > <goal name="copy.dep" description="copy dependencies"> > <j:forEach var="dep" items="${pom.dependencies}"> > <echo>${dep.getArtifactId()}.${dep.getExtension()}</echo> > <copy file="${pom.getDependencyPath(dep.getId())}" > tofile="lib/${dep.getArtifactId()}.${dep.getExtension()}"/> > </j:forEach> > </goal> > > </project> > > On Oct 19, 2004, at 11:15 AM, STRAYER, JON (SBCSI) wrote: > > >> > >>> Hi, > >>> > >>> Maven creates jar, but with name "PROJECT-version.jar" eg:- > >>> PROJECT-12.0.0.jar, > >>> is there anyway i can override this to create "project.jar" > >>> > >> This is not something which you would normally want to do > >> with maven. Jars and other artifacts are versioned for > >> numerous good reasons. > > > > How many people here are running their applications outside of a > > container? > > > > How do you handle setting the class path (when it changes with each > > release)? > > > > I ended up taking some code from the maven deploy plugin and modifying > > it to generate a class path from the pom. > > > > --------------------------------------------------------------------- > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > For additional commands, e-mail: [EMAIL PROTECTED] > > > > > > > --ming > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED]
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