Mike, Thanks for pointing that out, using java.lang.Number works as expected.
Mike Kienenberger wrote:
It's supposed to work as you'e described. As Dave says below, use "java.lang.Number" as your data type, and it'll work for both a Long and a Double. You can then use Number.doubleValue() no matter which underlying type was returned. http://java.sun.com/j2ee/javaserverfaces/1.1/docs/api/javax/faces/convert/NumberConverter.html "The getAsObject() method parses a String into an java.lang.Double or java.lang.Long...." On 11/7/05, Yannick Le Teigner <[EMAIL PROTECTED]> wrote:Hello, I use f:convertNumber in my application to display localized number value. Problam is that if the number entered in the input box by the user has any decimal digits (i.e. 14.75) then the returned number is a Double. If the number does not have any decimal digit (i.e 103), then the returned number is a Long. The only solution I have found is to put MyBean.value as an object of type Object, but I have to do type cast all over the place... <h:inputText value="#{MyBean.value}"> <f:convertNumber type="number" maxFractionDigits="2"/> </h:inputText> Has anyone found a way to force the type of the returned value? Thanks, Yannick
