Patrick Linskey wrote:
Hi,

Yeah, that sounds like something that you couldn't model directly. In
my initial reading, I hadn't noticed that you were creating an entity
for the join table.

Is it important that the B-A relation be unordered? If not, then you
could just model the A-B with ordering, and happen to get that
ordering also on the other side of the relation.

I'm not sure I see how..

Also, is there any reason why you're modeling the BRef table as an
entity, vs. just using two many-to-many relationships?

The motivation is this: If you need to apply an ordering constraint on a many-to-many relationship, the field on which the constraint is applied cannot be placed within either class. Instead it must be placed directly in the join table supporting the relation. This is not possible as far as i know with the current specification of @ManyToMany, @JoinTable and @OrderBy.

For instance, let's say that you have instances a1 and a2 of class A and b1 and b2 of class B. Both a1 and a2 reference b1 and b2, but the ordering of b1 and b2 are reversed for a1 and a2:

a1.bs = [b1, b2]
a2.bs = [b2, b1]

In this situation, the ordering constraint cannot be specified directly in class B. It must be placed in the join table supporting the relationship:

"A_B"
A  | B  | index
---------------
a1 | b1 | 1
a1 | b2 | 2
a2 | b1 | 2
a2 | b2 | 1

If you have a bidirectional relationship between A and B where the links must be ordered in both directions, you must use two separate join tables, but if only one side requires ordering, then you should be able to use a single join table to capture both directions of the relationship along with the unidirectional ordering constraint.

-Patrick

On Jan 25, 2008 3:46 PM, Andy Schlaikjer <[EMAIL PROTECTED]> wrote:
Hi Patrick,

Thanks for your response. I did see in documentation the note on
specifying the mapping of a bidirectional relation on only one side of
the relation, but in my case the nature of the bidirectional
relationship is a bit more constrained: the A to B relation is ordered,
whereas the B to A relation is unordered. I'm not aware of any mechanism
in JPA by which I can specify an "orderBy" column within a join table,
so I'm at a loss here.

Thanks,
Andy


Patrick Linskey wrote:
Hi,

If you're trying to model a bidirectional relationship, you should
only specify mapping info for one side and use the mappedBy annotation
property on the other side of the relation.

-Patrick

On 1/25/08, Andy Schlaikjer <[EMAIL PROTECTED]> wrote:
Hi all,

I was curious if/how I might get into trouble by reusing a table to
support mapping of an @Entity as well as a @JoinTable. Here's an example:

I have the following entities A, BRef, and B where a unidirectional
many-to-many relation between A and B is defined via BRef (acting here
as an explicit join table):

@Entity
class A {
   @Id
   protected long id;

   @OneToMany(mappedBy = "a")
   @OrderBy("idx")
   protected List<BRef> brefs;
}

@Entity
@Table(uniqueConstraints = @UniqueConstraint(columnNames = {"a_id",
"b_id"}))
class BRef {
   @Id
   protected long id;

   @ManyToOne(optional = false)
   protected A a;

   @ManyToOne(optional = false)
   protected B b;

   @Basic
   protected int idx;
}

@Entity
class B {
   @Id
   protected long id;
}

With this mapping (using the mysql DBDictionary), the following CREATE
TABLE statement reflects the BRef table:

CREATE TABLE `BRef` (
   `id` bigint(20) NOT NULL,
   `idx` int(11) default NULL,
   `a_id` bigint(20) default NULL,
   `b_id` bigint(20) default NULL,
   PRIMARY KEY  (`id`),
   UNIQUE KEY `a_id` (`a_id`,`b_id`),
   KEY `I_BREF_A` (`a_id`),
   KEY `I_BREF_B` (`b_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

Now I'd like to extend the mapping to include the reverse many-to-many
relation from B to A:

@Entity
class B {
   @Id
   protected long id;

   @OneToMany
   @JoinTable(
     name = "BRef",
     joinColumns = @JoinColumn(name = "b_id"),
     inverseJoinColumns = @JoinColumn(name = "a_id"),
     uniqueConstraints = @UniqueConstraint(columnNames = {"a_id", "b_id"})
   )
   protected Collection<A> as;
}

When I do this, the CREATE TABLE statement for table "BRef" changes
slightly (ordering of columns, names of indices):

CREATE TABLE `BRef` (
   `id` bigint(20) NOT NULL,
   `idx` int(11) default NULL,
   `b_id` bigint(20) default NULL,
   `a_id` bigint(20) default NULL,
   PRIMARY KEY  (`id`),
   UNIQUE KEY `a_id` (`a_id`,`b_id`),
   KEY `I_BREF_B_ID` (`b_id`),
   KEY `I_BREF_ELEMENT` (`a_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

So it is clear that the two separate mappings for table "BRef" are
competing with one another. How else might the OpenJPA runtime be
affected by this?

Thanks,
Andy

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