Hi all, I wrote this query here. select o from User as o where o.id in ( select valueInteger from UserPersistentParameter as o )
but I got <openjpa-1.2.1-r752877:753278 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: null at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:814) at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:775) at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:771) which isn't very helpful. I realized my error was in omitting the "o." prior to valueInteger. It should read like this: select o from User as o where o.id in ( select o.valueInteger from UserPersistentParameter as o ) Perhaps the exception could be a bit more descriptive. -- Daryl Stultz _____________________________________ 6 Degrees Software and Consulting, Inc. http://www.6degrees.com mailto:[email protected]
