I still got a problem
It work with a query but not with a find.
Code:
1: EntityTransaction transaction = em.getTransaction();
2: transaction.begin();
3: OpenJPAEntityManager kem = OpenJPAPersistence.cast(em);
4: FetchPlan fetchPlan = kem.getFetchPlan();
5: fetchPlan.removeFetchGroup(FetchGroup.NAME_DEFAULT);
6: fetchPlan.clearFetchGroups();
7: fetchPlan.clearFields();
8: fetchPlan.addField(AbstractCustomer.class, "name");
9: fetchPlan.addField(Order.class, "status");
10: OpenJPAQuery q = OpenJPAPersistence
.cast(kem
.createQuery("SELECT c FROM
AbstractCustomer c WHERE
c.customerId=:a"));
11: q.setParameter(1, 2);
12: AbstractCustomer customer1 = (AbstractCustomer)
q.getSingleResult();
13: AbstractCustomer customer2 =
kem.find(AbstractCustomer.class, 2);
14: System.out.println(customer1.getName());
15: System.out.println(customer2.getName());
16: transaction.rollback();
17: em.close();
Output:
32 pie-db-JAVA-SE INFO [main] openjpa.Runtime - Starting OpenJPA 1.2.2
829 pie-db-JAVA-SE TRACE [main] openjpa.jdbc.SQL - <t 21565531, conn
30463067> executing prepstmnt 25709120 SELECT t0.CUSTOMER_ID, t0.type,
t0.name FROM APP.CUSTOMER t0 WHERE (t0.CUSTOMER_ID = ?) [params=(int) 2]
844 pie-db-JAVA-SE TRACE [main] openjpa.jdbc.SQL - <t 21565531, conn
30463067> [15 ms] spent
891 pie-db-JAVA-SE TRACE [main] openjpa.jdbc.SQL - <t 21565531, conn
10520143> executing prepstmnt 30620267 SELECT t1.ORDER_ID, t1.status,
t1.total, t0.RESIDENTIAL_FREQUENT_CUSTOMER, t0.RESIDENTIAL_HOUSEHOLD_SIZE
FROM APP.CUSTOMER t0 LEFT OUTER JOIN APP.ORDERS t1 ON t0.OPEN_ORDER =
t1.ORDER_ID WHERE t0.CUSTOMER_ID = ? [params=(int) 2]
Roland Barcia
Roland Barcia
891 pie-db-JAVA-SE TRACE [main] openjpa.jdbc.SQL - <t 21565531, conn
10520143> [0 ms] spent
And if I comment the line 8 : fetchPlan.addField(AbstractCustomer.class,
"name");
The value of the line 14 is null
Can you help me ?
Thanks
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