The type of a field that represents persistent identity must be one of
java.lang.Integer, Long etc.  and well-specified by JPA specification. A
generic type (i.e. a type non-determinable at compile time) is not permitted
by spec. 

> OpenJpa implementation might be struggling to determine the "id" field
> type in my @MappedSuperclass

It is a struggle that OpenJPA is bound to lose, as any compiler will as
well. 
 



-----
Pinaki Poddar
Chair, Apache OpenJPA Project
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