Hi,
Both entities belong to different persistence units and have their own
entity managers. I have pasted the persistence.xml snippet below for both
the persistence files. The Zone entity in persistenceUnit1 has a field
property of Policy entity also in persistenceUnit1. This Policy entity is a
base class of another entity CustomPolicy which is in persistenceUnit2. I
am trying to persist the Zone with entity manager of persistenceUnit1. This
is when I hit the problem. If we cannot persist this way, then what could
be solution to this issue.
<persistence-unit name="PersistenceUnit1">
<jta-data-source>jdbc/db2connection</jta-data-source>
<class>mypack.src.Policy</class>
<class>mypack.src.Zone</class>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<validation-mode>NONE</validation-mode>
<properties>
<!-- Create the database tables on startup -->
<property name="openjpa.jdbc.SynchronizeMappings" value=
"buildSchema(ForeignKeys=true)"/>
<property name="openjpa.Log"
value="DefaultLevel=ERROR"/>
<property name="openjpa.jdbc.DBDictionary" value="db2"/>
<property name="openjpa.Multithreaded" value="true"/>
<property name="openjpa.jdbc.TransactionIsolation"
value="read-committed" />
</properties>
</persistence-unit>
<persistence-unit name="PersistenceUnit2">
<jta-data-source>jdbc/db2connection</jta-data-source>
<class>mycustom.src.CustomPolicy</class>
<class>mypack.src.Policy</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<validation-mode>NONE</validation-mode>
<properties>
<!-- Create the database tables on startup -->
<property name="openjpa.jdbc.SynchronizeMappings" value=
"buildSchema(ForeignKeys=true)"/>
<property name="openjpa.Log"
value="DefaultLevel=ERROR"/>
<property name="openjpa.jdbc.DBDictionary" value="db2"/>
<property name="openjpa.Multithreaded" value="true"/>
<property name="openjpa.jdbc.TransactionIsolation"
value="read-committed" />
</properties>
</persistence-unit>
Regards,
Akash
From: Rick Curtis <curti...@gmail.com>
To: users <users@openjpa.apache.org>,
Date: 10/22/2013 12:42 AM
Subject: Re: JPA exception while persistence into database
> That entity has a field associated with another entity. Both these
entities belong to different persistence units.
You can't persist a relationship from an Entity to another Entity that
belongs in a different persistence units. An EntityManager will only
operate against Entities that are a part of it's persistence unit
definition. Do you truly have two different persistence units, or do you
just have two different EntityManagers?
On Mon, Oct 21, 2013 at 11:50 AM, Akash Gunjal <akgun...@in.ibm.com> wrote:
> Hi,
>
> I am trying to persist an entity into the database. That entity has a
field
> associated with another entity. Both these entities belong to different
> persistence units. When trying to persist the entity I get the below
error.
>
> > Invalid parameter - Encountered unmanaged object
> "com.ibm.powersc.ts.policies.vlan.persistence.VLANPolicy@40004000" in
life
> cycle state unmanaged while cascading persistence via field
> "com.ibm.sc.core.persistence.Zone.policies<element:class
> com.ibm.sc.core.persistence.Policy>" during flush. However, this field
> does not allow cascade persist. You cannot flush unmanaged objects or
> graphs that have persistent associations to unmanaged objects.
> Suggested actions: a) Set the cascade attribute for this field to
> CascadeType.PERSIST or CascadeType.ALL (JPA annotations) or "persist" or
> "all" (JPA orm.xml),
> b) enable cascade-persist globally,
> c) manually persist the related field value prior to flushing.
> d) if the reference belongs to another context, allow reference to it by
> setting StoreContext.setAllowReferenceToSiblingContext().
>
>
> I tried to give cascade.All option to the field having entity reference,
> then I get an error message "This entity is not managed by this context".
>
> Regards,
> Akash
>
>
--
*Rick Curtis*
