On Thursday, January 7, 2010, Henry Rotzoll <[email protected]> wrote: > > Thanks Kris! > > "btn.activate();" did the trick!
Your control is a button as opposed to a toggle, and it's not active by default its DOM element gets "Inactive" class. When you activate it gets the "Active" class, so it's rendering changes. I don't understand why you need two classes and two ways to render the button. Cheers, -- Eric Lemoine Camptocamp France SAS Savoie Technolac, BP 352 73377 Le Bourget du Lac, Cedex Tel : 00 33 4 79 44 44 96 Mail : [email protected] http://www.camptocamp.com _______________________________________________ Users mailing list [email protected] http://openlayers.org/mailman/listinfo/users
