Hi,
in feature.attributes I have an empty object. One more problem is
how could i find the LonLat of the selected feature?
-------- Messaggio originale --------
Oggetto: Re: [OpenLayers-Users] Popup over GPX track
Data: Tue, 11 May 2010 13:24:13 -0400
Mittente: Charles Galpin <[email protected]>
A: Francesco <[email protected]>
Francesco, the feature attributes will be in feature.attributes
(feature.attributes.name etc)
hth,
charles
On May 11, 2010, at 12:43 PM, Francesco wrote:
Hi,
I'm trying to display a popup on mouse over GPX track. This is the
code used to load the track:
var lgpx = new OpenLayers.Layer.Vector("Track", {
style: {strokeColor: 'red', strokeWidth: 10,
strokeOpacity: 0.5},
projection: map.displayProjection,
strategies: [new OpenLayers.Strategy.Fixed()],
protocol: new OpenLayers.Protocol.HTTP({
url: 'gpx.php',
format: new OpenLayers.Format.GPX()
})
});
map.addLayer(lgpx);
lgpx.events.register('loadend',lgpx,function() {
var bounds = this.getDataExtent();
map.zoomToExtent(bounds);
});
var hoverSelect = new OpenLayers.Control.SelectFeature(lgpx, {
hover: true,
onSelect: function(feature) {
--------------> Here I want to display a popup with info from the GPX file
},
onUnselect: function(feature) {
if (feature.popup) {
map.removePopup(feature.popup);
feature.popup.destroy();
delete feature.popup;
}
}
});
map.addControl(hoverSelect);
hoverSelect.activate();
I cannot find a way to get the currently selected track segment and
extract attributes to display inside the popup.
Any idea?
Tnx
Francesco
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