Looking at the regular expressions, it get stranger and stranger. Someone else wanted to delete all lines starting with %. Regular expressions should do it with:

^%*$

^% is a % at the start of a paragraph
* is any number of characters
$ a paragraph break

It doesn't work. If I try just ^%*, only the % gets deleted. If * represents any number of characters, that should delete everything.
tc


David Welton wrote:

On Thu, 17 Feb 2005 10:40:17 -0500, Anthony Chilco
<[EMAIL PROTECTED]> wrote:

Hi David,
Very weird. You can search for row breaks (shift-enter), but
you can't replace with them. This is from the regular
expressions help page:


Yeah I had read that, but hoped that there was some way to get around
it:-(  I guess I could fiddle with the XML, but that doesn't strike me
as being a particularly pleasant approach.


\n
Finds a hard row break that was inserted with Shift+Enter.
To change row breaks into paragraph breaks, enter \n in the
Search for and Replace with boxes, and then click the
Replace all button.

From this I infer that \n means row break when used in the
search box and it means paragraph break when used in the
replace box. You can search for paragraph breaks using
regular expressions with $ in the search box, but you don't
have the option to replace with a row break because the \n
expression means paragraph break when replacing. It seems to
be deliberate when you read the help, but doesn't look right
to me.


Yes, to me it seems there ought to be one way to specify a character,
visible or not, in both fields.

Thanks for your help in any case,

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