[users] Re: Basic Macros: undocumented statement and syntax

[Matt Needles]

Andrew Douglas Pitonyak wrote:
Matt Needles wrote:
I have searched and re-searched the online help, but the Type 
statement is not documented, it seems.

I document them on Page 29 of my book :-)
Also the construct used below in declaring a string variable to be of 
a certain length is not documented, either.

You can not declare a variable to be of a specified length. At least I 
have never heard of this. You could use an array of characters, but you 
can not do that directly by definition inside of your own data types :-( 
The following line does NOT declare a string of length 4. I might 
consider the acceptance of this form an error unless it is for some kind 
of compatibility.

 Dim s As String * 4
This is the way you do this in VisualBasic.  It worked, too, from what I 
see in the OOo Macro Variable Watch window.

On a related note, I tried using it with the following macro code and 
got the error indicated by the REM lines in the code:

Option Explicit
Type tAddrRec
    sRecType as string * 1    ' "I" for persons, "O" for Organizations
    sRecStatus as string * 1' "A" active, "D" deleted, "H" held
    iRecID as integer    ' starts with 1
    sLName as string * 35
    sFname as string * 35
    sAddr1 as string * 35
    sAddr2 as string * 35
    sCity as string * 25
    sState as string * 5
    sPostal as string * 10
    iCtryCode as integer
    sPhone1 as string * 15
    sPhone2 as string * 15
    sPhone3 as string * 15
    sEmail as string * 64
    sNotes as string * 60
End Type
Sub Main
    Dim myFile as Integer, lRecLen as Long
    Dim myAddrRec as tAddrRec
    myFile = FreeFile
REM ***** Error occurs on next line. *****
    lRecLen = Len(myAddrRec)

The Len() routine expects a String. 
Not according to the Help:
Len Function [Runtime]
Returns the number of characters in a string, or the number of bytes 
that are required to store a variable.

I assume that is why you get the 
error. What did you expect for the length of a user defined type?

I expect the length of the struct I defined.  Again, this is the way to 
do this in VB.

Thanks for your reply, Andrew.
Matt Needles
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