Brian Barker wrote:
> At 03:34 23/10/2008 +0000, Girard Aquino wrote:
>> Hi! I have a data sheet that has names, dates they attended and 
>> whether or not they did attend. i would like to see how many people 
>> actually attended for the first quarter, and/or by month. So for 
>> example, i would have 15 names listed and scheduled for the month of 
>> feb 2008, but only 10 of them actually attended. i have the dates 
>> they should attend on column b, and have added another column c for 
>> status/comments (this is where i place either attended, confirmed or 
>> ). i got the total number of people who attended using 
>> countif(xxx;"=attended"). any suggestions of how to do this?
>
> The problem here is not so much how to combine two criteria, of 
> course, but that COUNTIF() appears only to be able to examine a single 
> vector (e.g. column) of values.  I don't see any way in which you can 
> get COUNTIF() to examine the date and attendance columns in a single 
> formula.  So a solution is to combine these values into a single 
> parameter, which you can then count with COUNTIF().
>
> For example, if you wanted totals for months you could copy
>      =MONTH(B1)&YEAR(B1)&C1
> down a new column.  You would then get values such as "22008attended" 
> for someone who attended in February 2008 and perhaps "42008confirmed" 
> for someone who failed to attend in April 2008.
>
> Alternatively,
>      =INT((MONTH(B1)-1)/3+1)&YEAR(B1)&C1
> will give you values such as "12008attended" for someone who attended 
> in the first quarter of 2008 and "22008confirmed" for someone who 
> failed to attend in the second quarter of 2008.
>
> You can then evaluate the relevant totals by applying COUNTIF() to the 
> new column.  If you prefer, you can hide this extra column, of course.
>
> It is also possible to use the so-called database function DCOUNT() to 
> do this sort of thing.  (That's a "database" function in a Calc 
> spreadsheet, not to be confused with a Base database.)  This allows 
> you to apply conditions to more than one column simultaneously.  It 
> works, but I don't think it makes the solution any easier.
>
> I trust this helps.
>
> Brian Barker
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
>
>
>
I got the new column, but I am having difficulty representing characters 
in the countif(). I am using =COUNTIF(D8:D133;"\"). i tried 
to replace the formatting of the new column into text, but can't get the 
desired result. I know it's probably a problem with my syntax.


_________________________________________________________________

Reply via email to