Pradeep Srinivas wrote: > On Friday 21 August 2009 00:52:57 Johnny Rosenberg wrote: >> 2009/8/20 Jonathan Kaye <[email protected]>: <snipped by Jonathan> > Thanks for the offer - I will, in return, treat you to some great > Indian snacks if you brought the bottle to India !!!! Oh Pradeep. You have found my biggest weakness. I love Indian food and if I don't get any regularly, my mind stops working :( I am fortunate to have a girlfriend who is an excellent cook of Indian food so I don't suffer too much but it's hard to find papadams here. She does make excellent chutneys (mango/plum, etc.) and wonderful currys. But I've never been to Indian and that is a big gap in my life. My daughter-in-law is from a Punjabi family and my grandson is named Ravi. Sadly my financial situation does not permit such trips but the offer is well received indeed. > > I write this in response to Johnny Rosenberg - Johnny, you can use > something like what I have given below: > > Search for : ([:space:]){2,} > Replace with : $1 > /* i.e., you do not need to use the " " syntax here */ > > The $1 in the replace says "the pattern matched by what is inside the > first pair of parenthesis : i.e., what is within the '(' and ')', > namely the "[:space:]" portion." Here is my second question, Pradeep, since you know regular expressions quite well. I want to match a string from the start of the record to the first full-stop (if any) in the record. That part is easy: ^.*\. gives me what I want. Now the hard part: in the replace field, how can I refer to the material matched by .* ? I would like to surround the matched material with « at the beginning and » at the end. So, for example, if a have a record like this: delete.me, I would like to replace it with this: «delete»me Is this possible? Thanks again, Jonathan
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