Den 2010-09-12 14:19:27 skrev Malte Timmermann
<[email protected]>:
If you are sure it's always 10 chars long:
Search: ([0-9][0-9][0-9])([0-9][0-9][0-9])([0-9][0-9][0-9][0-9])
Replace: $1-$2-$3
[0-9] means finding a digit
() is for grouping, so you can use the found string in the replace
statement
$<n> is result of group <n>
HTH,
Malte.
Or, if you didn't like my suggestion yesterday about
([:digit:]{3})([:digit:]{3})([:digit:]{4}), then a mix of both suggestions
could be:
([0-9]{3})([0-9]{3})([0-9]{4})
Replace is the same in all three cases:
$1-$2-$3
{x} means x instances of what's to the left of it.
So 3 digits followed by three digits followed by four digits will be
replaced by the first three digits followed by a minus sign and so on.
--
Kind regards
Johnny Rosenberg
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