On 1/22/19 5:54 PM, Nathanaël Blanchet wrote:
Hi all,
If anyone uses latest pycurl 7.43 provided by pip or ansible tower/awx,
any ovirtsdk4 calling will issue with the log:
The full traceback is:
WARNING: The below traceback may *not* be related to the actual failure.
File "/tmp/ansible_ovirt_auth_payload_L1HK9E/__main__.py", line 202,
in <module>
import ovirtsdk4 as sdk
File
"/opt/awx/embedded/lib64/python2.7/site-packages/ovirtsdk4/__init__.py",
line 22, in <module>
import pycurl
fatal: [localhost]: FAILED! => {
"changed": false,
"invocation": {
"module_args": {
"ca_file": null,
"compress": true,
"headers": null,
"hostname": null,
"insecure": true,
"kerberos": false,
"ovirt_auth": null,
"password": "VALUE_SPECIFIED_IN_NO_LOG_PARAMETER",
"state": "present",
"timeout": 0,
"token": null,
"url": "https://acore.v100.abes.fr/ovirt-engine/api";,
"username": "admin@internal"
}
},
"msg": "ovirtsdk4 version 4.2.4 or higher is required for this module"
}
The only way is to set the version of pycurl with
pip install -U "pycurl == 7.19.0"
(Before this, in tower/awx, you should create venv)
What's the version of AWX, where pycurl 7.43 is provided? I use latest
and I have 7.19. But anyway, I've tried to update to 7.43, and this
worked for me with nss:
$ source venv/awx/bin/activate
$ export PYCURL_SSL_LIBRARY=nss; pip install pycurl --compile --no-cache-dir
$ python -c 'import pycurl; print pycurl.version'
PycURL/7.43.0.2 libcurl/7.29.0 NSS/3.36 zlib/1.2.7 libidn/1.28 libssh2/1.4.3
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