On 07/03/2011 09:04 AM, Jiri Krutil wrote:
Using the C++ messaging client, I would like to declare a binding from
exchange E to queue Q without declaring the exchange or the queue;
assuming both already exist. (I want to avoid their declaration because
I don't know all their attributes, so in case they don't exist, I want
to get an error.)
Is this perhaps possible by creating a Sender to an exchange that always
exists (say amq.direct) and specifying my binding between E and Q in the
Address (in the x-bindings list under node)?
Yes, but the x-bindings should then appear in the link, not the node.
The node bindings are evaluated only if the node needs to be created.
The link bindings are evaluated whenever a 'link' to or from the node,
i.e. a sender or receiver, is created.
E.g. Assuming an exchange my-exchange and queue my-queue (which were
separately configured or pre-exist), I can create a sender to:
my-exchange/my-key; {link:{x-bindings:[{exchange:my-exchange,
queue:my-queue, key:my-key}]}}
which on creation will result in the binding being created. Note however
that the binding will be destroyed when the sender is closed.
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