Thanks for clearing that up in a nice way.

On Fri, Dec 2, 2016 at 8:31 PM, Gordon Sim <[email protected]> wrote:

> On 02/12/16 20:14, James Franco wrote:
>
>> I am trying to understand what happens when we send a message to a queue
>> with a little more perspective.
>>
>> Supose I have an exchange called *my-ex  *that has a queue called *my_q*
>> and this queue is bound to the exchange with the binding key *my_bid*.
>> Now when I send a message to the queue directrly like this
>>
>>  ./spout my_q/someSubject This is a bind test
>>>>
>>>
>> The message is received when I do this
>>
>> ./drain my_q
>>>>
>>>
>> Now I have two questions regarding this:
>>
>> 1- since the address being used is my_q and there is no exchange mentioned
>> (or the exchnage is blank) in the address does the broker first check the
>> default exchange and then look consecutively into  other exchanges until
>> it
>> finds the specified queue ?
>>
>
> No. The client will send the message to the default exchange with a
> routing key of 'my_q'. If a queue named 'my_q' exists, the default exchange
> is guaranteed to have a binding with key 'my_q' for the my_q queue.
>
> 2-From my understanding so far is that when a message is sent to an
>> exchange instead of a queue then depending on the type of exchange the
>> message is routed to a specific queue based on the routing id and binding
>> id of the queue , however if the message is sent to the  a queue directly
>> (instead of an exchnage name) then routing id and binding id do not matter
>> and the message will be delivered to the queue. Is my understanding
>> correct
>> ?
>>
>
> At the protocol level, messages are *always* sent to an exchange. The qpid
> messaging API presents a higher level abstraction where you just send to or
> receive from an address. If the address is a queue, and if you are using
> AMQP 0-10 (rather than 1.0), this will cause the client to send to the
> default exchange (which is really just a hack to allow you to emulate
> sending to a queue which that protocol version did not support).
>
>
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