By default, using std::vector<c++-type> is encoded as an AMQP array,
whereas std::vector<proton::value> is encoded as an AMQP list. So, to
create an array of lists of differing types, for example:
std::vector<proton::value> list1 = {uint8_t(0), uint8_t(1)};
std::vector<proton::value> list2 = {true, false};
std::vector<std::vector<proton::value> > array = {list1, list2};
works ok. However, how does one define an array of arrays of differing
types? For example:
std::vector<uint8_t> array1 = {uint8_t(0), uint8_t(1)};
std::vector<bool> array2 = {true, false};
std::vector<std::vector<##> > array3 = {array1, array2};
What is ##? Unless all the sub-arrays are of the same type, it is not
possible to define a single type here. If I use proton::value (which
would make it indistinguishable from the array of lists above), I get a
compile error:
could not convert '{array1, array2}' from '<brace-enclosed initializer
list' to 'std::vector<std::vector<proton::value> >'
What is the correct way to create an array of arrays of differing types?
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