Hi Sam, Thanks, that's exactly what I was doing. I just wanted to know if there is a direct way to do that.
Regards, --Bhathiya On Fri, Jul 6, 2012 at 2:20 AM, sam ” <[email protected]> wrote: > check the type of value. if it is object, {}, it's a node. otherwise, it's > property. > > in python: > def ls(self, path=None): > if path is None: > path = self.cwd > > path = os.path.join(self.cwd, path) > > l = [] > d = self.get_json(path) > for k,v in d.iteritems(): > * if isinstance(v, dict): > l.append(k + '/')* > else: > l.append(k) > return l > > > the bold part is test if value is dictionary (node), and appends / > > > > On Thu, Jul 5, 2012 at 4:12 PM, Bhathiya Jayasekara > <[email protected]>wrote: > > > Hi, > > > > I want to get a node's child nodes in jason (at least the names of them) > > without the main node's properties, because when I get a node as > > /path/to/node.1.json , I can't distinguish properties and child nodes by > > looking their names. Is there a way to do that? > > > > Thank you. > > > > --Bhathiya > > >
