Hey Julian,
Oke, thanks!
Greetings,
Roy
> On 03 Mar 2016, at 13:11, Julian Sedding <jsedd...@gmail.com> wrote:
>
> Hello Roy
>
> XPath queries allow ordering by a property:
> /jcr:root/A//element(*, nt:unstructured) [
> jcr:contains(property, ‘value’)
> ] order by @otherProperty descending
>
> If you want the child order, you should iterate over the child node
> using the API:
>
> NodeIterator children = session.getNode("/A").getNodes();
> while (children.hasNext()) {
> Node child = children.nextNode();
> // do something with it
> }
>
> In other words: query results don't know about the sibling order of nodes.
>
> Regards
> Julian
>
>
>
> On Wed, Mar 2, 2016 at 7:13 PM, Roy Teeuwen <r...@teeuwen.be> wrote:
>> Hello all,
>>
>> I have a node A with subnodes B,C,D and am creating a JCR query to retrieve
>> some of the subnodes by using the following XPATH query:
>>
>> /jcr:root/A//element(*, nt:unstructured) [
>> jcr:contains(property, ‘value’)
>> ]
>>
>> The problem that I am facing at this moment that the order it retrieves the
>> elements seem te be random. Sometimes it gives back B,D and sometimes D,B.
>> What I would like is that it always gives back the order that the nodes have
>> below A has in the jcr repository, is it possible to pass this to the query
>> (either XPath or an SQL for the same result)
>>
>> Thanks
>> Roy
