Philip Prindeville wrote: >> header L_INCOMPETENT1 ALL =~ /\\r\\n/ >> >> header L_INCOMPETENT2 ALL =~ /\\r\\n\s?$/ >> >> header L_INCOMPETENT3 ALL =~ /\\r\\n\s?\n/ > > Ok, I tried #3 and it worked, as you said... But leaving the \s? > didn't. > > I'm confused. What exactly is in the pattern buffer when the match > for ALL is run? And why does taking the \s? fail? What is it > matching against?
ALL is a multiline string containing all the headers. By default $ only matches at the end of a string and NOT at internal newlines. You can get the behavior you want by using the /m modifier: header L_INCOMPETENT4 ALL =~ /\\r\\n\s?$/m or by specifying [\s\n] as a class: header L_INCOMPETENT5 ALL =~ /\\r\\n[\s\n]?/ $ perl -e 'print "a\nb" =~ /a$/' $ perl -e 'print "a\nb" =~ /a$/m' 1 -- Matthew.van.Eerde (at) hbinc.com 805.964.4554 x902 Hispanic Business Inc./HireDiversity.com Software Engineer
