Hi,
Is there a port which I have to open to allow pyzor to run properly? I keep
having the below error.
[26217] dbg: util: executable for pyzor was found at /usr/bin/pyzor
[26217] dbg: pyzor: pyzor is available: /usr/bin/pyzor
[26217] dbg: info: entering helper-app run mode
[26217] dbg: pyzor: opening pipe: /usr/bin/pyzor check <
/tmp/.spamassassin26217aJlAZctmp
[26219] dbg: util: setuid: ruid=0 euid=0
[26217] dbg: pyzor: [26219] finished: exit=0x0100
[26217] dbg: pyzor: got response: Traceback (most recent call last):\n File
"/usr/bin/pyzor", line 4, in ?\n pyzor.client.run()\n File
"/usr/lib/python2.4/site-packages/pyzor/client.py", line 934, in run\n
ExecCall().run()\n File "/usr/lib/python2.4/site-packages/pyzor/client.py",
line 188, in run\n if not apply(dispatch, (self, args)):\n File
"/usr/lib/python2.4/site-packages/pyzor/client.py", line 264, in check\n
response = runner.run(server, (digest, server))\n File
"/usr/lib/python2.4/site-packages/pyzor/client.py", line 725, in run\n
response = apply(self.routine, varargs, kwargs)\n File
"/usr/lib/python2.4/site-packages/pyzor/client.py", line 58, in check\n
self.send(msg, address)\n File
"/usr/lib/python2.4/site-packages/pyzor/client.py", line 77, in send\n
self.socket.sendto(mac_msg_str, 0, address)\nsocket.error: (1, 'Operation
not permitted')
regards
