Hallo everybody.

My question is about how could I implement a recursion in tapestry 5? exactly in a tree component. I have a collection of nodes with a Node father and a Collection children, then in the tml I have a loop and check if the actual node is father or not, but I want execute again the same control for each children.

<t:loop t:source="source" t:value="item">
           <t:if t:test="father">
               <tr>
                   <td width="1%" valign="top" style="cursor:pointer">
<img src="images/plus.gif" border="0" onclick="javascript:UTILS_Change_Display('${item.identifier}')"/>
                   </td>
                   <td width="1%" valign="top">
<img src="images/folder.gif" border="0" alt="${item.identifier}"/>
                   </td>
<td width="1%" nowrap="true" valign="top" onClick="javascript:UTILS_Change_Color('name_${item.identifier}', 'black', '#0000ff');"> <span id="name_${item.identifier}" style="cursor:pointer">
                           ${item.name}
                       </span>
                   </td>
                   <td width="*" valign="top">
<div id="${item.identifier}" name="${item.identifier}" style="display:none"> <table border="0" cellspacing="0" cellpadding="0"> Here I want implements the recursion (at the momment I have another loop): <t:loop t:source="item.children" t:value="item">
                                   <tr>
                                       <td width="1%">
</td> <td width="1%" valign="top" style="padding-right:1mm"> <img src="images/folder.gif" border="0"/>
                                       </td>
                                       <td valign="top">
                                           ${item.name}
                                       </td>
                                   </tr>
                               </t:loop>
                           </table>
                       </div>
                       &#160;
                   </td>
               </tr>
           </t:if>
</t:loop>

I'm new in tapestry and I don't know if is possible or not.

Thank you very much in advanced.


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