registry.getService("serviceId", Object.class)
On Thu, Feb 28, 2013 at 12:30 PM, antalk <nab...@vankalleveen.net> wrote:
> Not really, i still have to specify the full class of the interface.
>
> I just want to get a service by it's ID without specifying any class or
> interface.
>
>
>
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--
BR
Ivan
