Antonio Petrelli a écrit :
> 2007/8/5, Chris Pratt <[EMAIL PROTECTED]>:
>
>> I'm trying to create a tile that generates a menu where the menu items
>> are sensitive to the page they're on, but for some reason I can't seem
>> to figure out how to find the current page. When I try:
>>
>> <!--
>> req.getPathInfo() = ${pageContext.request.pathInfo}
>> req.getPathTranslated() = ${pageContext.request.pathTranslated}
>> req.getRequestURI() = ${pageContext.request.requestURI}
>> req.getRequestURL() = ${pageContext.request.requestURL}
>> req.getServletPath() = ${pageContext.request.servletPath}
>> -->
>>
>> it generates:
>>
>> <!--
>> req.getPathInfo() =
>> req.getPathTranslated() =
>> req.getRequestURI() = /layout/default-layout.jsp
>> req.getRequestURL() =
>> http://anodyzed.planetpratt.com/layout/default-layout.jsp
>> req.getServletPath() = /layout/default-layout.jsp
>> -->
>>
>> which tells me what layout I'm using, but not what the actual request
>> was. Is there any way to get access to the page name?
>>
>
> I suppose the answer is "no", at least directly.
> Your problem will be the same even if you don't use Tiles, because,
> when you forward to a JSP page, the latest request URI will be that
> JSP page.
> But the question is: do you want to create a customized menu depending
> on the definition name?
> In this case, I think you should look the concept of "preparer":
> http://tiles.apache.org/tutorial/advanced/preparer.html
>
> Ciao
> Antonio
>
>
>
It is indeed a problem with the Servlet API, not tiles. The solution
came with Servlet 2.4 : the following request attributes hold the
original request information after a forward or an include.
javax.servlet.forward.request_uri
javax.servlet.forward.context_path
javax.servlet.forward.servlet_path
javax.servlet.forward.path_info
javax.servlet.forward.query_string
javax.servlet.include.request_uri
javax.servlet.include.context_path
javax.servlet.include.servlet_path
javax.servlet.include.path_info
javax.servlet.include.query_string
Hope this helps
Nick
