Hi, I would like to ask about my observation on Tomcat run on different ways. First, I run Tomcat on the command-line. I encountered no errors and I can access my webapp succesfully. Then, I try to re-run Tomcat as Windows service. I execute the ff command: C:\Tomcat\bin>NET START Tomcat5 The Apache Tomcat service is starting. The Apache Tomcat service was started successfully. Then I access the url of my webapp. I got HTTP Status 500- error, saying: javax.servlet.ServletException: javax.xml.transform.TransformerException: javax.xml.transform.TransformerException: Unable to find file: shared/header.xsl My xsl files were located at TOMCAT_HOME/webapps/MyApp/xsl. I put this line on my setclasspath.bat: set CLASSPATH=%JAVA_HOME%\lib\tools.jar set CLASSPATH=%CLASSPATH%;%CATALINA_HOME%\webapps\MyApp\xsl;%CATALINA_HOME%\webapps\MyApp\xml
Basically, that's the only change I made on my Tomcat instance' config files, and it run successfully when I'm runnin my Tomcat on the command-line. Why is it that i got an HTTP error when I'm running the same webapp on Tomcat, which is started as a Windows service? Is there anything I have to set for me to run it as a Windows service, successfully? I really need a reply. I'm getting confused. Thanks a lot. lalyne Send instant messages to your online friends http://uk.messenger.yahoo.com
