Jasper in turn uses JDT to compile JSPs into servlets and JDT is currently 
only JDK 1.4 compliant. To use 1.5 features in your JSP you will thus have 
to replace jasper.

This questions has been brought up a couple of times so search the 
archives or look at 
http://tomcat.apache.org/tomcat-5.5-doc/jasper-howto.html

Regards Thomas






Dola Woolfe <[EMAIL PROTECTED]>
11-01-2006 01:07
Besvar venligst til "Tomcat Users List"

 
        Til:    Tom Cat <tomcat-user@jakarta.apache.org>
        cc: 
        Vedr.:  Tomcat 5.5 and java 1.5 features.



Hi,

I'd like to use java 1.5 features in my jsp code, in
particular generics. But the jasper compiler really
doesn't like it. Any setting to fix this:

org.apache.jasper.JasperException: Unable to compile
class for JSP

An error occurred at line: 2 in the jsp file:
/MBInit.jsp
Generated servlet error:
The method name() is undefined for the type Object

An error occurred at line: 2 in the jsp file:
/MBInit.jsp
Generated servlet error:
Type mismatch: cannot convert from Object to Message

An error occurred at line: 2 in the jsp file:
/MBInit.jsp
Generated servlet error:
Type mismatch: cannot convert from Object to Vector



org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)

org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)

org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:397)

org.apache.jasper.compiler.Compiler.compile(Compiler.java:288)

org.apache.jasper.compiler.Compiler.compile(Compiler.java:267)

org.apache.jasper.compiler.Compiler.compile(Compiler.java:255)

org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:556)

org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:293)

org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:291)

org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)

javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

Many thanks in advance!

Dola

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