On 3/31/2013 10:20 AM, Kevin Jenkins wrote:
If I run tomcat7w.exe (windows) there is a tab where I can set the initial
and maximum memory pool to 2560. However, I don't want to use tomcat7w.exe,
I just want to run the batch file manually (startup.bat). However, I can't
figure out how to set these memory pool values for startup.bat to use.
I read somewhere to create C:\apache-tomcat-7.0.37\bin\setenv.bat which
contains
SET JAVA_OPTS=-Xms2560 -Xmx2560
However, it doesn't work. If I run startup.bat, instead of launching the
webserver it just prints some messages and that's it. No webserver is
started.
C:\apache-tomcat-7.0.37\bin>startup.bat
Using CATALINA_BASE: "C:\apache-tomcat-7.0.37"
Using CATALINA_HOME: "C:\apache-tomcat-7.0.37"
Using CATALINA_TMPDIR: "C:\apache-tomcat-7.0.37\temp"
Using JRE_HOME: "C:\Program Files\Java\jdk1.6.0_43"
Using CLASSPATH:
"C:\apache-tomcat-7.0.37\bin\bootstrap.jar;C:\apache-tomc
at-7.0.37\bin\tomcat-juli.jar"
C:\apache-tomcat-7.0.37\bin>
From the documentation:
-Xmsn
Specify the initial size, in bytes, of the memory allocation pool.
This value must be a multiple of 1024 greater than 1MB
-Xmxn
Specify the maximum size, in bytes, of the memory allocation
pool. This value must a multiple of 1024 greater than 2MB.
So maybe you are trying to specify 2.5 GB, but you've really specified
2.5 KB. This isn't going to work.
Try the following in setenv.bat:
set "CATALINA_OPTS=-Xms2560m -Xmx2560m"
. . . . just my two cents.
/mde/
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