Hello, I am using Tomcat 8.0.28 on Windows 10 and am having a problem with the Rewrite Value. I must include the escaped form of an ampersand '%26' in the output URL.
My rewrite.config has the following: RewriteCond %{QUERY_STRING} ^(.*&)?SCID=8(&.*)?$ RewriteRule ^/(product|specs|avail-options|avail-category)\.php$ /Product.action?select=Model+4+\%26+4C [R=301,L,NE] I am escaping the percent sign with a backslash, and I have tried using the NE flag. However, Tomcat always is treating the percent symbol as a back reference to the above RewriteCond. If I don't have a second capture group, then I get a 500 error from a NullPointerException. I was working with the documentation on this page: http://tomcat.apache.org/tomcat-8.0-doc/rewrite.html The desired output URL would be: http://www.domain.com/Product.html?select=Model+4+%26+4C In the example given for the NE flag on the page reference above, the percent sign is escaped by a backslash to prevent it from being treated as a back-reference. This is not working for me. Instead I get: http://www.domain.com/Product.action?select=Model+4+\null6+4C Where the "null" is due to an empty second back-reference. I believe this is a bug in that it is not escaping the percent sign (making it impossible to create the %26 in the redirect URL). Or am I misunderstanding something here? As a side question, shouldn't an empty back-reference be blank instead of adding 'null' to the URL? Joseph B Aldrich Junior Java Developer P: 800.981.1540 | F: 715.254.0996 4848 Industrial Park Rd. Stevens Point. 54481 --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org