On Mon, Nov 4, 2019 at 2:55 PM Mark Thomas <ma...@apache.org> wrote:
>
> On 04/11/2019 12:59, Alexander Stöcker wrote:
> > My code is basically just:
> >
> > Tomcat tomcat = new Tomcat();
> > tomcat.getConnector();
> > tomcat.setPort(8080);
> >
> > Context context = tomcat.addContext("/context", new
> > File(".").getAbsolutePath());
> >
> > // servlet
> > Tomcat.addServlet(context, "myServlet", new MyServlet());
> > context.addServletMappingDecoded("/hello", "myServlet");
> >
> > // websocket
> > context.addApplicationListener(MyWSContextListener.class.getName());
> >
> > // run
> > tomcat.start();
> > tomcat.getServer().await();
> >
> >
> > The WsContextListener is adding an Endpoint when contextInitialized()
> > is called. Setting a Breakpoint shows that the code is actually
> > executed. The Servlet is working but when I'm trying to connect to the
> > endpoint ("ws://localhost:8080/context/endpoint") I get a 404. On Fine
> > debug output I can see, that this exception is thrown, whenever a
> > connection is requested:
>
> You need to configure the default servlet. Otherwise the mapper looks at
> the URI, sees that it doesn't match any known servlets and rejects the
> request with a 404 before the WebSocket filter has a chance to handle
> the request.
>
> Mark
>
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>
Indeed, that solved the Problem. I would have never been able to solve
that just from documentation or examples... After some googling on
"default servlet" I found this SO thread which gave me the solution:
https://stackoverflow.com/questions/6349472/embedded-tomcat-not-serving-static-content
TL;DR: You could either write:
Wrapper defaultServlet = context.createWrapper();
defaultServlet.setName("default");
defaultServlet.setServletClass("org.apache.catalina.servlets.DefaultServlet");
defaultServlet.setLoadOnStartup(1);
context.addChild(defaultServlet);
context.addServletMappingDecoded("/", "default");
or just
Tomcat.initWebappDefaults(context);
thanks & best regards
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