Hi guys, Quick question, How can I get the following properties applied to jax-rs? dropRootElement = true supportUnwrapped = true I saw this post
http://openejb.979440.n4.nabble.com/Configuring-Apache-CXF-in-TomEE-td4660207.html which outlines how to do it with an openejb-jar.xml and a resources.xml, but how can I do it with just system.properties and/or openejb.xml? I've tried things like: openejb.jaxrs.providers.auto=true openejb.cxf.jax-rs.providers=org.apache.cxf.jaxrs.provider.json.JSONProvider org.apache.cxf.jaxrs.provider.json.JSONProvider.dropRootElement = true org.apache.cxf.jaxrs.provider.json.JSONProvider.supportUnwrapped = true also tried this in openejb.xml <Resource id="json" class-name="org.apache.cxf.jaxrs.provider.json.JSONProvider"> dropRootElement = true supportUnwrapped = true </Resource> but no to avail. Chris Christo --- Twitter: https://twitter.com/ChrisChristo7 Tumblr: http://chrischristo7.tumblr.com LinkedIn: http://uk.linkedin.com/in/chrischristo GitHub: https://github.com/ChrisChristo
