Im reading this topic:
http://tomee-openejb.979440.n4.nabble.com/Configuring-Apache-CXF-in-TomEE-td4660207.html
Then i created an resouces file but i dont see any changes in my arrays (of
length 1)
This is resources.xml under WEB-INF file with this content:
<resources>
<Service id="json"
class-name="org.apache.cxf.jaxrs.provider.json.JSONProvider">
serializeAsArray = true
</Service>
</resources>
And again this is my openejb-jar.xml
<openejb-jar xmlns="http://www.openejb.org/openejb-jar/1.1"; xmlns:xsi="
http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.openejb.org/openejb-jar/1.1 ">
<pojo-deployment class-name="jaxrs-application">
<properties>
cxf.jaxrs.providers =
com.fasterxml.jackson.jaxrs.json.JacksonJaxbJsonProvider
</properties>
</pojo-deployment>
</openejb-jar>
What im doing wrong?
2014-10-18 19:09 GMT-05:00 José Luis Cetina <[email protected]>:
> Hi, i need to set the serializeAsArray property to true, but where do i
> have to put it? in openejb-jar.xml?
>
>
>
> This is my openejb-jar.xml
>
> <openejb-jar xmlns="http://www.openejb.org/openejb-jar/1.1"; xmlns:xsi="
> http://www.w3.org/2001/XMLSchema-instance";
> xsi:schemaLocation="http://www.openejb.org/openejb-jar/1.1 ">
> <pojo-deployment class-name="jaxrs-application">
> <properties>
> cxf.jaxrs.providers =
> com.fasterxml.jackson.jaxrs.json.JacksonJaxbJsonProvider
> </properties>
> </pojo-deployment>
> </openejb-jar>
>
> --
> -------------------------------------------------------------------
> *José Luis Cetina*
> -------------------------------------------------------------------
>
--
-------------------------------------------------------------------
*José Luis Cetina*
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