If you need to access your component's parent in a safe way, the first
method when you can do that is onBeforeRender().
-Matej
On 9/3/07, Sam Hough <[EMAIL PROTECTED]> wrote:
>
>
> Would that not be too soon? The Button could not have been added to a form
> yet?
>
> My particular use case is that I have a chunk of code that returns a tree
> of
> components that may not yet be attached to a page/form...
>
>
> Matthijs Wensveen-2 wrote:
> >
> > Or maybe:
> >
> > public AjaxButton(String id)
> > {
> > this(id, getForm());
> > }
> >
> >
> > This could work the same for AjaxFallbackButton.
> >
> > Matthijs
> >
> > Johan Compagner wrote:
> >> It is needed i guess if we say that the method
> >> protected abstract void onSubmit(AjaxRequestTarget ajaxrequesttarget,
> >> Form
> >> form1);
> >>
> >> needs a form parameter that can't be null
> >>
> >> Also i see something strange in the AjaxButton because if you dont give
> >> the
> >> form then the form parameter
> >> can be null:
> >>
> >> public AjaxButton(String id)
> >> {
> >> this(id, null);
> >> }
> >>
> >> public Form getForm()
> >> {
> >> if(form != null)
> >> return form;
> >> else
> >> return super.getForm();
> >> }
> >>
> >> public AjaxButton(String id, final Form form)
> >> {
> >> super(id);
> >> this.form = form;
> >> add(new AjaxFormSubmitBehavior("onclick", form) {
> >>
> >> protected void onSubmit(AjaxRequestTarget target)
> >> {
> >> AjaxButton.this.onSubmit(target, form);
> >> }
> >>
> >> protected void onError(AjaxRequestTarget target)
> >> {
> >> AjaxButton.this.onError(target, form);
> >> }
> >>
> >> i think this is wrong, but maybe it was on purpose?
> >> i think it should be:
> >>
> >> public AjaxButton(String id)
> >> {
> >> this(id, null);
> >> }
> >>
> >> public Form getForm()
> >> {
> >> if(form != null)
> >> return form;
> >> else
> >> return super.getForm();
> >> }
> >>
> >> public AjaxButton(String id, final Form form)
> >> {
> >> super(id);
> >> this.form = form;
> >> add(new AjaxFormSubmitBehavior("onclick", form) {
> >>
> >> protected void onSubmit(AjaxRequestTarget target)
> >> {
> >> AjaxButton.this.onSubmit(target, getForm());
> >> }
> >>
> >> protected void onError(AjaxRequestTarget target)
> >> {
> >> AjaxButton.this.onError(target, getForm());
> >> }
> >>
> >> So that we return the given form or try to find one.
> >>
> >> johan
> >>
> >>
> >>
> >> On 9/3/07, Sam Hough <[EMAIL PROTECTED]> wrote:
> >>
> >>> Since neither AjaxButton or Button require Form in the constructor why
> >>> does
> >>> AjaxFallbackButton? Seems a shame to make it required if not really
> >>> needed...
> >>>
> >>> I'm not quite clear from the source or comments what the difference is
> >>> in
> >>> AjaxButton between the behaviour from the two different
> constructors...
> >>> --
> >>> View this message in context:
> >>>
> http://www.nabble.com/AjaxFallbackButton-really-require-Form-in-constructor--tf4370843.html#a12457890
> >>> Sent from the Wicket - User mailing list archive at Nabble.com.
> >>>
> >>>
> >>> ---------------------------------------------------------------------
> >>> To unsubscribe, e-mail: [EMAIL PROTECTED]
> >>> For additional commands, e-mail: [EMAIL PROTECTED]
> >>>
> >>>
> >>>
> >>
> >>
> >
> >
> > --
> > Matthijs Wensveen
> > Func. Internet Integration
> > W http://www.func.nl
> > T +31 20 4230000
> > F +31 20 4223500
> >
> >
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> > To unsubscribe, e-mail: [EMAIL PROTECTED]
> > For additional commands, e-mail: [EMAIL PROTECTED]
> >
> >
> >
>
> --
> View this message in context:
> http://www.nabble.com/AjaxFallbackButton-really-require-Form-in-constructor--tf4370843.html#a12462188
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
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