Thanks very much.
>but it is not just like it was after it has been created is it? it is
>currently holding a value from the request. anywho:
>
>secondchoiceSelected=null;
>secondchoicedropdownchoice.clearInput();
>
>and you will have what you want.
>
>-igor
>
>
>On Feb 4, 2008 7:36 PM, <[EMAIL PROTECTED]> wrote:
>> The following is the code sample
>>
>> class webpage
>> String secondchoiceSelected;
>>
>>
>> }
>> new Firstdropdownchoice( ){
>> onSelectionChange{
>> secondchoiceSelected = null;
>> }
>>
>>
>> I did set to null. This issue is that the displayed value is
>> the first item of the new list, instead of "Choose One", it is not
>> displaying the old secondVarSelected since I already set it to null.
>> Basically, when the dropdownchoice is redisplayed and is model is
>> null, it is supposed to display the same as the first created. It does
>> not appear this way.
>>
>>
>>
>>
>>
>> >whe the first is submitted you have to set the second one's model object
>to
>> >null
>> >
>> >-igor
>> >
>> >
>> >On Feb 4, 2008 4:59 PM, <[EMAIL PROTECTED]> wrote:
>> >> Hello:
>> >> I am using two dropdownchoices, after the first select, the second would
>get
>> >data on the fly using the first choice. The first round everything is
>fine
>> >with both displaying "Choose One" and selecting the first one set the
>correct
>> >second one list of choice with "Choose One" still displaying on the second
>so
>> >that one could click on it to pick the right one. After the first round, I
>> >select a different value in the first one, which resets correctly the
>second
>> >one' list as in the first round but strangely this time, the 'Choose One"
>> >display is gone in the second dropdownchoice. Instead it shows the first
>item
>> >of the new list. I used the wicket-examples sample code as basis and use
>> >getObject() to load the correct list when selection on the first changed.
>> >> Thanks
>> >
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