Re: Form.getMethod() throws Exception

[EMAIL PROTECTED] Mon, 18 Feb 2008 15:43:34 -0800

Sorry that I was not clear enough.

Even though I have a specific scenario in my application, the questionis more general. Let me rephrase what I'm after.I want to avoid whatever parameters I submit to my response page frombeing displayed in the browsers url field.


For instance, if my submit method contains

setResponsePage(ResponsePage.class, newPageParameters("password=NotSoSecret"));

I will seehttp://<myserver>/<webapp>/html/ResponsePage/password/NotSoSecret in thebrowser when the response page has been loaded.


Hope this was a little bit clearer.

/Jörgen

Martijn Dashorst skrev:

I don't understand what you are trying to achieve.

setResponsePage goes to another page. If you don't want to go to
another page, then don't set response page.

Martijn

On 2/18/08, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:

Ah, so I was half correct ;)

What is the best practice to get around this? Should I store my
parameters in my Session class and pick them up again when in
MyResponseClass?

And one more thing. Sorry for not signing my earlier mails.

Thanks for your help.

BR,
Jörgen


Henrik Lundahl skrev:

Hi

The parameters are left out of the request URL in the request that brings
you to the onSubmit method, but the response URL will contain the
PageParameters you set for the MyResponseClass page.


BR,
Henrik Lundahl



2008/2/18, [EMAIL PROTECTED] <[EMAIL PROTECTED]>:

Hello.

It was just for debugging purposes.

I wanted to see if I used GET or POST. I know from the code that POST is
used as default (unless stated otherwise in the markup), but I just
wanted it confirmed.

With my very limited (next to nothing) knowledge about web coding in
general I thought that when using POST any parameter passed on is not
shown in the URL. This is however the case when I submit using

...
onSubmit(){
mySumbitButton.setResponsePage(MyResponseClass.class, new
PageParameters("myKey=myValue"));
}
...


Martijn Dashorst skrev:

Don't call this method in a constructor. The component isn't added to
the page yet, and therefore doesn't know its markup causing it to fail
to find the method="foo" tag.

Why do you want to call  this method in a constructor?

Martijn

On 2/18/08, [EMAIL PROTECTED] <[EMAIL PROTECTED]>

wrote:

Hello all.

When calling the getMethod from a subclass of a Form component an
exception is thrown.
When looking in the code I see the following comment just before the
exception is thrown in Component.java:
// This should never happen since Page always has associated markup

If I out comment this call then my app runs like a charm :), so this
looks like a bug to me. Is this a known problem?

org.apache.wicket.WicketRuntimeException: Unable to find parent with

associated markup

     at org.apache.wicket.Component.findParentWithAssociatedMarkup(

Component.java:1218)

     at org.apache.wicket.MarkupFragmentFinder.find(

MarkupFragmentFinder.java:50)

     at org.apache.wicket.Component.locateMarkupStream(Component.java

:3614)

     at org.apache.wicket.Component.getMarkupAttributes(Component.java

:1359)

     at org.apache.wicket.markup.html.form.Form.getMethod(Form.java

:1378)

at

se.jorgenpersson.web.manager.TemplateManagement$ListTemplateForm.<init>(
TemplateManagement.java:54)

     at se.jorgenpersson.web.manager.TemplateManagement.<init>(

TemplateManagement.java:28)

     at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
     at java.lang.Class.newInstance0(Class.java:355)
     at java.lang.Class.newInstance(Class.java:308)
     at org.apache.wicket.session.DefaultPageFactory.newPage(

DefaultPageFactory.java:58)

at

org.apache.wicket.request.target.component.BookmarkablePageRequestTarget.newPage
(BookmarkablePageRequestTarget.java:262)

at

org.apache.wicket.request.target.component.BookmarkablePageRequestTarget.getPage
(BookmarkablePageRequestTarget.java:283)

at

org.apache.wicket.request.target.component.BookmarkablePageRequestTarget.processEvents
(BookmarkablePageRequestTarget.java:210)

at

org.apache.wicket.request.AbstractRequestCycleProcessor.processEvents(
AbstractRequestCycleProcessor.java:90)

     at org.apache.wicket.RequestCycle.processEventsAndRespond(

RequestCycle.java:1166)

     at org.apache.wicket.RequestCycle.step(RequestCycle.java:1241)
     at org.apache.wicket.RequestCycle.steps(RequestCycle.java:1316)
     at org.apache.wicket.RequestCycle.request(RequestCycle.java:493)
     at org.apache.wicket.protocol.http.WicketFilter.doGet(

WicketFilter.java:354)

     at org.apache.wicket.protocol.http.WicketServlet.doGet(

WicketServlet.java:121)

     at javax.servlet.http.HttpServlet.service(HttpServlet.java:690)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
     at

org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(
ApplicationFilterChain.java:290)

     at org.apache.catalina.core.ApplicationFilterChain.doFilter(

ApplicationFilterChain.java:206)

     at org.apache.catalina.core.StandardWrapperValve.invoke(

StandardWrapperValve.java:233)

     at org.apache.catalina.core.StandardContextValve.invoke(

StandardContextValve.java:175)

     at org.apache.catalina.core.StandardHostValve.invoke(

StandardHostValve.java:128)

     at org.apache.catalina.valves.ErrorReportValve.invoke(

ErrorReportValve.java:102)

     at org.apache.catalina.core.StandardEngineValve.invoke(

StandardEngineValve.java:109)

     at org.apache.catalina.connector.CoyoteAdapter.service(

CoyoteAdapter.java:263)

     at org.apache.coyote.http11.Http11Processor.process(

Http11Processor.java:844)

at

org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(
Http11Protocol.java:584)

     at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(

JIoEndpoint.java:447)

     at java.lang.Thread.run(Thread.java:619)




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Re: Form.getMethod() throws Exception

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