Actually there's one more problem. You cannot upload files by means of Ajax -
search the mailinglist for solutions to this problem.
As for the AjaxFormSubmitBehavior: it is sufficient to add it to the form,
there's no need to add it to the button as well. You don't even have to make
the button a wicket component, just add in in your HTML. That applies to
submit buttons. If it's something like a cancel button that shouldn't submit
the form, you should use a AjaxButton and set defaultformprocessing to
false. AFAIK using a Button in the form with ajax does only call the form's
onsubmit method.
hope that helps, regards
Michael
liny wrote:
>
> Hi,sir:
>
> I am newbie.
> I have a file upload web page and want to use AJAX to submit form.
> So I use IndicatingAjaxButton and add an AjaxFormSubmitBehavior to this
> button.
> Here is code snippet:
> ajaxFormSubmitBehavior = new AjaxFormSubmitBehavior(uploadForm,
> "onclick")
> {
> protected void onSubmit(AjaxRequestTarget arg0)
> {
> System.out.println("ajaxFormSubmitBehavior - onSubmit");
> }
>
> protected void onError(AjaxRequestTarget arg0)
> {
> System.out.println("ajaxFormSubmitBehavior - onError");
> }
> };
>
> indicatingAjaxBtn.add(ajaxFormSubmitBehavior);
> uploadForm.add(indicatingAjaxBtn);
>
> There are problems:
> 1. When click indicatingAjaxBtn button on html page, indicator
> disappeared. Why? How to solve it?
> 2. When click indicatingAjaxBtn button on html page, why it doesn't
> execute its protected onSubmit() method?
>
-----
Michael Sparer
http://talk-on-tech.blogspot.com
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