Which proxy are it? apache2 httpd? Matthew Hanlon wrote:
Hmm. I on further thought, "Referer" is not the proper header to use. Something more like this instead:public String getUrl(MyResource res) { PageParameters params = new PageParameters(); params.put(Constants.MY_RESOURCE, res.getId()); WebRequestCycle cycle = (WebRequestCycle)RequestCycle.get(); String urn = cycle.urlFor(MyResponsePage.class, params).toString(); String host = cycle.getWebRequest().getHttpServletRequest().getHeader("Host"); String context = cycle.getWebRequest().getHttpServletRequest().getContextPath(); StringBuffer url = new StringBuffer(); url.append("http:// ").append(host).append(context).append("/").append(urn); return url.toString(); } On Fri, Jun 27, 2008 at 9:58 AM, Matthew Hanlon <[EMAIL PROTECTED]> wrote:I was having a problem getting the full url of a page or resource after deploying my application behind a proxy. I was previously doing the following: public String getUrl(MyResource res) { PageParameters params = new PageParameters(); params.put(Constants.MY_RESOURCE, res.getId()); WebRequestCycle cycle = (WebRequestCycle)RequestCycle.get(); return RequestUtils.toAbsolutePath(cycle.urlFor(MyResponsePage.class, params).toString()); } However, after deploying behind a proxy, I was expecting to get " http://my.domain.com/MyResourcePage/resouce/xxx"; and instead was getting " http://localhost:8080/MyResourcePage/resouce/xxx";. So I adjusted to doing the following: public String getUrl(MyResource res) { PageParameters params = new PageParameters(); params.put(Constants.MY_RESOURCE, res.getId()); WebRequestCycle cycle = (WebRequestCycle)RequestCycle.get(); String urn = cycle.urlFor(MyResponsePage.class, params).toString(); String referer = cycle.getWebRequest().getHttpServletRequest().getHeader("Referer"); String context = cycle.getWebRequest().getHttpServletRequest().getContextPath(); PrependingStringBuffer url = new PrependingStringBuffer(urn); url.prepend(referer.substring(0, referer.indexOf(context) + context.length() + 1)); return url.toString(); } It's working, but I was curious if anyone had any input or a better method of accomplishing this. Thanks! Regards, Matthew. -- Matthew Rollins Hanlon http://squareoftwo.org _____________________ Hanlon's Razor: "Never attribute to malice that which can be adequately explained by stupidity." http://wikipedia.org/wiki/Hanlon's_razor<http://wikipedia.org/wiki/Hanlon%27s_razor>
-- -Wicket for love Nino Martinez Wael Java Specialist @ Jayway DK http://www.jayway.dk +45 2936 7684 --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
