http://google.com/search?q=wicket+ajax+visible
On Sat, Jul 12, 2008 at 12:44 AM, vishy_sb <[EMAIL PROTECTED]> wrote:
>
> Hi all,
>
> I have a page where I have put an AjaxFallBackButton() and also have a Panel
> on it. I want to make the panel visible or invisible by clicking the button.
> Kindly refer to the code below:
>
> //Code for the TestPage
> public TestPage() {
> Form form = new Form("form");
> add(form);
> button = new AjaxFallbackButton("button", form) {
> private static final long serialVersionUID = 1L;
>
> @Override
> protected void onSubmit(AjaxRequestTarget target, Form
> form) {
> target.addComponent(testPanel);
> testPanel.setVisible(!testPanel.isVisible());
> }
> };
> form.add(button);
> testPanel = new TestPanel("testPanel");
> form.add(testPanel);
> testPanel.setOutputMarkupId(true);
> }
>
> //Code for the Panel
> public TestPanel(String id) {
> super(id);
> add(new Label("testPanel", "Testing New Panel"));
> }
>
> The problem is that when I click the button, the Panel becomes invisible.
> However when I click it again the panel doesn't show up until or unless the
> entire page is refreshed. I am newbie to Wicket and I know I am making a
> basic mistake but I havn't been able to figure this out. Kindly let me know
> where I am going wrong. Thank in advance!!!
>
> vishy
> --
> View this message in context:
> http://www.nabble.com/Problem-making-Panel-visible-using-AJAX-tp18413807p18413807.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
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