Do you have any form validation going on? If yes implement the onError
method on the ajax button. Example:
form.add(new AjaxButton("order") {
@Override
protected void onError(AjaxRequestTarget target, Form form) {
//Ops we got some errors, show them in a feedback panel
target.addComponent(feedbackPanel);
}
@Override
protected void onSubmit(AjaxRequestTarget target, Form form) {
//Do whatever you need here :)
setResponsePage(Index.class);
}
}.setOutputMarkupId(true));
Hope that helps.
2008/8/5 Bertrand DATAS <[EMAIL PROTECTED]>
> Hello All,
>
> I encounter a problem while I am using an AjaxButton.
>
> In my form page i create an Ajaxbutton that I attach to a markupContainer
> and in my HTML I add the folowwing HTML code :
> <input type="button" value=">>" wicket:id="selection" />
>
> The button is set default form processing to false.
>
> The problem is that when i click on this button nothing happens !!
> I have the same problem with ana AjaxSubmitLink.
>
> I use the Wicket framework 1.3.4.
>
>
> Can someone help me to see what is wrong with that button ??
>
> Thanks
>
> Bertrand
>
