Thanks For Reply,
As you said i will go with,
but just take a look with this code snippnet,
String servletName = ((WebApplication)
Application.get()).getWicketServlet().getServletName();
StringBuffer buf = new StringBuffer();
buf.append('/').append(servletName ).append('/').append(HELP_LOCATION)
.append("/index.html#").append(helpPageClassName);
this buf will be passes as url string to external link.so as your reply if i
try,
((WebApplication) Application.get()).getWicketFilter()-----------how do i
get servletname by this.
Regards,
Swapnil.
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