And of course don't forget to add the button or a parent component to the ajaxrequesttarget as well.
On Wed, May 6, 2009 at 11:58 AM, Janos Cserep <[email protected]> wrote: > AFAIR a button's label comes from it's Model. So you should do: > > new AjaxButton("preview"){ > > public void onSubmit(AjaxRequestTarget target, Form form){ > String label = getModelObject(); // or > getDefaultModelObject(); if 1.4 > if ("click".equals(label) { > getModel().setObject("unclick); // or > getDefaultModel().setObject("unclick") in case you're at 1.4 > } > } > }.setModel("click); > > > On Wed, May 6, 2009 at 11:44 AM, nino martinez wael > <[email protected]> wrote: >> Maybe to it with an attribute modifier.. I cant remember ajaxbutton.. >> >> 2009/5/6 Per Newgro <[email protected]>: >>> Maybe you could add two buttons and set the other visible? >>> >>> Cheers >>> Per >>> >>> --------------------------------------------------------------------- >>> To unsubscribe, e-mail: [email protected] >>> For additional commands, e-mail: [email protected] >>> >>> >> >> --------------------------------------------------------------------- >> To unsubscribe, e-mail: [email protected] >> For additional commands, e-mail: [email protected] >> >> > --------------------------------------------------------------------- To unsubscribe, e-mail: [email protected] For additional commands, e-mail: [email protected]
