Hi Mathias, hi all,
thanks for your help, I didn't know the
AjaxFormChoiceComponentUpdatingBehavior so far.
I now have the problem, that it jumps into the onUpdate method just once
(when I click on a checkbox for the first time). If I click again on the
same or any other checkbox, nothing happens. Does anyone have an
explanation for that?
Thank you
Philipp
This may confuse the web user quite a bit. It's preferred to send the request
each time or cache it maybe.
Form form = new Form( "form" );
List SITES = Arrays.asList(new String[] { "The Server Side", "Java
Lobby",
"Java.Net" });
final List<String> values = new LinkedList<String>();
final CheckBoxMultipleChoice c = new
CheckBoxMultipleChoice("site", new
Model(), SITES );
c.add( new AjaxFormChoiceComponentUpdatingBehavior(){
@Override
protected void onUpdate(AjaxRequestTarget target) {
System.out.println( c.getModelObject() );
}
});
form.add( c );
add( form );
In this onUpdate you could send to server, cache or whatever.
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