Hi,
I have an AjaxFormSubmitBehavior where I don't pass the form parameter
in the constructor, but have overridden the getForm() method to find the
related form. (The form is not parent of the button this behavior is
attached to, so can not be found by the behavior itself).
When I "click" on the button attached, the form is submitted nicely, but
after the onSubmit call I get this exception:
java.lang.NullPointerException
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:142)
at
org.apache.wicket.ajax.AjaxEventBehavior.respond(AjaxEventBehavior.java:166)
at
org.apache.wicket.ajax.AbstractDefaultAjaxBehavior.onRequest(AbstractDefaultAjaxBehavior.java:299)
at
org.apache.wicket.request.target.component.listener.BehaviorRequestTarget.processEvents(BehaviorRequestTarget.java:113)
at
org.apache.wicket.request.AbstractRequestCycleProcessor.processEvents(AbstractRequestCycleProcessor.java:92)
at
org.apache.wicket.RequestCycle.processEventsAndRespond(RequestCycle.java:1240)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1319)
Having a look at the source it seems there is a but at this line in
AjaxFormSubmitBehavior:
@Override
protected void onEvent(AjaxRequestTarget target)
{
...
if (form.findParent(Page.class) != null)
...
}
I think that should be :
... getForm().findParent(Page.class)
unless, there is a good reason not to be so?
Btw; I am using wicket version 1.4rc4.
Cheers
Zoltan