This is an awkward way to do it, and still doesn't set the selected
value back into his model.
The golden rule of DropDownChoice is: objects in the list must be of the
same type as the model object. If you want your model to be updated with
an int, you have to give DDC a list of Integer. The second rule is that
you use a ChoiceRenderer to convert this value (the int) to a display
value:
class MyDomainClass {
private int selection;
}
MyDomainClass myobj;
add(new DropDownChoice("ddc",
new PropertyModel(myobj, "selection"),
Arrays.asList(1, 2, 3),
new ChoiceRenderer() {
public Object getDisplayValue(Object value) {
// value is one of the objects from the list,
// the one that the user selected
Integer i = (Integer) value;
// This function maps 1 to "abc" and so on...
return getName(i);
})
);
jk
On Mon, Jul 27, 2009 at 12:36:39PM -0700, Mathias Nilsson wrote:
>
> class Choice{
> private int id;
> private Stringvalue;
>
> // getters and setters
> }
>
> List<Choice> choices = new LinkedList<Choice>();
> Choice c = new Choice();
> c.setId( 1 );
> c.setValue( "abc" );
>
> choices.add( c );
>
> // add the other values
>
>
> // The choice with id 1 will be selected.
> DropDownChoice drop = new DropDownChoice( "drop" , new Model( c ) , choices,
> new ChoiceRenderer( "value" , "id" ) );
>
> --
> View this message in context:
> http://www.nabble.com/DropDownChoice-with-ID-and-Value-tp24686742p24686931.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
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