Or use the web developer tools in FF and use "view generated source".
-- Jeremy Thomerson http://www.wickettraining.com On Mon, Nov 16, 2009 at 9:42 AM, Igor Vaynberg <[email protected]>wrote: > source only shows the initial load, not the changes made via ajax > executed javascript. use firebug to view the actual dom structure. > > -igor > > On Mon, Nov 16, 2009 at 6:16 AM, Muro Copenhagen <[email protected]> > wrote: > > Hi, > > > > I am using the wicket AbstractAjaxTimerBehavior, that checks if a job i > have > > executed has finished. > > > > When it has finished, i have a link i want to display. > > > > I have also added an attribut modifier to the link, that will add a > > javascript onclick to the link. > > > > My problem is that the changes made inside the AbstractAjaxTimerBehavior > is > > not shown when i use show source. > > > > But it actually displays the changes on the web page. > > > > How come it displays the changes, but i can't see the changes when i use > > show source ? > > Can i force wicket/the browser to auto render/display the changes when > the > > timer has finished. > > > > My concern is that the javascript i have added to the link will not be > > triggered, since it is not shown on the source. > > > > Here is a snapshot of my code: > > > > // senere link tracking > > link.add(new AttributeModifier("onclick", true, new > > Model("webTracking.trackEvent('test');"))); > > final AsyncronEventExecuter e = new AsyncronEventExecuter(...); > > > > add(new AbstractAjaxTimerBehavior(Duration.milliseconds(1000)) { > > protected void onTimer(final AjaxRequestTarget target) { > > if (e.isFinished()) { > > stop(); > > target.addComponent(link.setVisible(true)); > > } > > } > > > > > > Thanks in advance > > > > Best Regards > > Muro > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [email protected] > For additional commands, e-mail: [email protected] > >
